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An electron of mass m and a photon have same energy E. The ratio of de-Broglie wavelengths associated with them is
Options
(a) (E/2m)¹∕₂
(b) c(2mE)¹∕₂
(c) 1/c (2m/E)¹∕₂
(d) 1/c (E/2m)¹∕₂
Correct Answer:
1/c (E/2m)¹∕₂
Explanation:
λₑ = h / √2mE,
λp = hc / E,
E = hc / λp
λₑ / λp = (h / √2mE) (E / hc)
= 1/c √(E / 2m)
=1/c (E/2m)¹∕₂
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