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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When a string is divided into three segments of length l₁, l₂ and l₃ the fundamental
- If in an experiment for determination of velocity of sound by resonance tube
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- The damping force on an oscillator is directly proportional to the velocity.
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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