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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two cities are 150 km apart. Electric power is sent from one city to another city
- A condenser of 250 μF is connected in parallel to a coil of inductance of 0.16 mH
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- The range of voltmeter is 10V and its internal resistance is 50Ω.
- The young’s modulus of steel is twice that of brass. Two wires of same length
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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