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| ⇨ |
Acetylene, on reacting with formaldehyde under high pressure, gives
Options
(a) propanol
(b) propyl alcohol
(c) allyl aldehyde
(d) butyndiol
Correct Answer:
butyndiol
Explanation:
HC ≡ CH + HCHO (Acetylene) → HC ≡ C – CH₂OH (Formaldehyde)
HC ≡ C – CH₂OH + H – C = O → HOCH₂C ≡ CCH₂OH ( But – 2- yn-1,4-diol)
Related Questions: - MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- Which of the following has a tendency for covalent compound formation
- Cresol is
- A 2.5 mol sample of N₂H₄ loses 25 mol of electrons in being converted
- The number of sigma and pi-bonds in but-1-ene-3-yne are
Topics: Hydrocarbons
(84)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- MnO₄²⁻ (1 mole) in neutral aqueous medium is disproportionated to
- Which of the following has a tendency for covalent compound formation
- Cresol is
- A 2.5 mol sample of N₂H₄ loses 25 mol of electrons in being converted
- The number of sigma and pi-bonds in but-1-ene-3-yne are
Topics: Hydrocarbons (84)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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C2H2+2HCOH=OHCH2CCCH2OH