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A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The potential difference applied to an X-ray tube is 5 kV and the current through it
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- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- The area of cross-section of a steel wire (Y=2.0×10¹¹ N/m²) is 0.1 cm².
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Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5