| ⇦ | 
| ⇨ |
A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface by a constant horizontal force F. The area of cross-section of the plank is A. The compressive strain on the plank in the direction of the force is
Options
(a) F/AY
(b) 2F/AY
(c) F/2AY
(d) 3F/AY
Correct Answer:
F/AY
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A juggler maintains four balls in motion,making each of them to rise
- A round disc of moment of inertia i₂ about its axis perpendicular to its plane
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
Topics: Properties of Bulk Matter
(130)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- ₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³
- A juggler maintains four balls in motion,making each of them to rise
- A round disc of moment of inertia i₂ about its axis perpendicular to its plane
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
Topics: Properties of Bulk Matter (130)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply