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A transistor is operated in common-emitter configuration at Vᵥ = 2 V such that a change in the base current from 100 µA to 200 µA produces a change in the collector current from 5 mA to 10 mA. The current gain is
Options
(a) 100
(b) 150
(c) 50
(d) 75
Correct Answer:
50
Explanation:
∆Iₑ = ∆Iₘ + ∆Iₙ
β = ∆Iₙ / ∆Iₘ
∆Iₙ = (10 – 5)10⁻³ = 5 x 10⁻³ A
∆Iₘ = (200 – 100)10⁻⁶ = 100 x 10⁻⁶ A
β = 5 x 10⁻³ / 100 x 10⁻⁶ = 5/100 x 1000 = 50
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Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two waves are represented by the equations y₁ = a sin (?t + kx + 0.57) m
- To demonstrate the phenomenon of interference, we require two sources which emit
- Wires A and B are made from the same material. A has twice the diameter and three times
- The magnetic susceptibility does not depend upon the temperature in
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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