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A thin semicircular conducting ring (PQR) of radius r is falling with its plane vertical in a horizontal magnetic field B, as shown in the figure. The potential difference developed across the ring when its speed is v, is
Options
(a) zero
(b) Bvπr²/2 and P is at higher potential
(c) πrBv and R is at higher potential
(d) 2rBv and R is at higher potential
Correct Answer:
2rBv and R is at higher potential
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ohm’s law is not applicable except to
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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