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A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm is put in water (refractive index = 4/3) , its focal length is
Options
(a) 0.15 m
(b) 0.30 m
(c) 0.45 m
(d) 1.20 m
Correct Answer:
1.20 m
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Ray Optics
(94)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz.
- During mean life of a radioactive element, the fraction that disintegrates is
- A thin glass(refractive index 1.5) lens has optical power of -5D in air.
- α-particles, deuterons and protons of same energy are moving in a perpendicular
- A bucket full of water is revolved in a vertical circle of 2m
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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According to lens maker’s formula
1f=(μ−1)(1R1−1R2)
where μ=μLμM
Here, μL=32, μM=43, R1=+30cm, R2=−30cm
∴1f=(3243−1)(130−1−30)
=(18)(230)
1f=14×30=1120
or f=120cm=1.2m