| ⇦ |
| ⇨ |
A string is stretched between fixed points seperated by 75 cm. It is observed to have resonant frequencies of 420 Hz and 315 Hz. There are no other resonant frequencies between these two. Then, the lowest resonant frequency for this string is
Options
(a) 10.5 Hz
(b) 105 Hz
(c) 1.05 Hz
(d) 1050 Hz
Correct Answer:
105 Hz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Suppose the kinetic energy of a body oscillating with amplitude A and at a distance
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- Suppose the kinetic energy of a body oscillating with amplitude A and at a distance
- The point of suspension λ of a simple pendulum with normal time period T₁ is moving
- A stone is dropped from a height h. It hits the ground with a certain momentum P. If the same stone is dropped from a height 100
- The radius of germanium nuclide is measured to be twice the radius of ₄⁹Be.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply