| ⇦ | 
| ⇨ |
A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular to a magnetic field of intensity 0.9 Wbm⁻². The induced emf across the conductor is
Options
(a) 5.04 V
(b) 1.26 V
(c) 2.52 V
(d) 25.2 V
Correct Answer:
2.52 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The maximum particle velocity in a wave motion is half the wave velocity.
- A particle with total energy E is moving in a potential energy region U(x)
- Bragg’s law for X-rays is
- After 300 days, the activity of a radioactive sample is 5000 dps
- The current gain of a transistor in common base configuration is 0.96.
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The maximum particle velocity in a wave motion is half the wave velocity.
- A particle with total energy E is moving in a potential energy region U(x)
- Bragg’s law for X-rays is
- After 300 days, the activity of a radioactive sample is 5000 dps
- The current gain of a transistor in common base configuration is 0.96.
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply