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A solution of nickel sulphate in which nickel rod is dipped is diluted 10 times. the reduction potential of Ni at 298 K
Options
(a) decreases by 60 mV
(b) decreases by 30 mV
(c) decreases by 30 V
(d) increases by 30 mV
Correct Answer:
decreases by 30 mV
Explanation:
Let the initial concentration of Ni²⁺ = a. Since the solution is diluted 10 times, its concentration = a/10. Applying Nernst equation, E = E⁰ – 0.0591/2 log a /a/10. E = E⁰ – 0.030(log 10) ⇒ E = E⁰ – 0.030. Therefore the reduction potential of Ni decreases by 30 mV.
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Topics: Electrochemistry and Chemical Kinetics
(87)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is non-permissible?
- Number of σ and π- bonds in acetylene is
- How many electrons in an atom with atomic number 105 can have (n + l) = 8
- Identify the correct order of the size of the following elements:
- The normality of solution containing 31.5g of hydrated oxalic acid (H₂C₂O₄.2H₂O)
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Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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