⇦ | ⇨ |
A small object of uniform density rolls up a curved surface with an initial velocity v’.It reaches upto a maximum height of 3v² / 4g with respect to the initial position.The object is
Options
(a) ring
(b) solid sphere
(c) hollow sphere
(d) disc
Correct Answer:
disc
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A generator at a utility company produces 100 A of current at 4000 V. The voltage
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- The product of pressure and volume hve thesame units as the product of
- What is the time taken by moon light to reach earth?
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- A particle executing SHM with amplitude of 0.1 m. At a certain instant,
- The product of pressure and volume hve thesame units as the product of
- What is the time taken by moon light to reach earth?
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Conservation of mechanical energy:
Initial total energy=Final total energy
i.e. (K.E.+P.E.)1=(K.E.+P.E.)2
1/2mv^2{1+K^2/R^2}+0=0+mgh
1/2mv^2{1+K^2/R^2}=mg(3v^2/4g)
1/2{1+K^2/R^2}=3/4
1+K^2/R^2=3/2
Hence,K^2/R^2=1/2
which implies that the small object is disc