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A small object of uniform density rolls up a curved surface with an initial velocity v’.It reaches upto a maximum height of 3v² / 4g with respect to the initial position.The object is
Options
(a) ring
(b) solid sphere
(c) hollow sphere
(d) disc
Correct Answer:
disc
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
- The current in the coil of inductance 5H decreases at the rate of 2 A/s
- If vₑ is escape velocity and vₙ is orbital velocity of a satellite
- A radioactive substance emits n beta particles in the first 2 s and 0.5 n beta
- A boat which has a speed of 5 kmh⁻¹ in still water crosses river of width 1 km long
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Conservation of mechanical energy:
Initial total energy=Final total energy
i.e. (K.E.+P.E.)1=(K.E.+P.E.)2
1/2mv^2{1+K^2/R^2}+0=0+mgh
1/2mv^2{1+K^2/R^2}=mg(3v^2/4g)
1/2{1+K^2/R^2}=3/4
1+K^2/R^2=3/2
Hence,K^2/R^2=1/2
which implies that the small object is disc