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A small object of uniform density rolls up a curved surface with an initial velocity v’.It reaches upto a maximum height of 3v² / 4g with respect to the initial position.The object is
Options
(a) ring
(b) solid sphere
(c) hollow sphere
(d) disc
Correct Answer:
disc
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The total energy of a simple harmonic oscillator is proportional to
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
- The potential energy of a long spring when stretched by 2 cm is U.
- The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Conservation of mechanical energy:
Initial total energy=Final total energy
i.e. (K.E.+P.E.)1=(K.E.+P.E.)2
1/2mv^2{1+K^2/R^2}+0=0+mgh
1/2mv^2{1+K^2/R^2}=mg(3v^2/4g)
1/2{1+K^2/R^2}=3/4
1+K^2/R^2=3/2
Hence,K^2/R^2=1/2
which implies that the small object is disc