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A rod of weight W is supported by two parallel knife edges A and B is in equilibrium in a horizontal position. The knives are at a distance d from each other. The centre of mass of the rod is at distance x from A. The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x)/x
(c) W(d-x)/d
(d) Wx/d
Correct Answer:
W(d-x)/d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
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