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A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium, in a horizontal position.The knives are at a distance d from each other.The centre of mass of the rod is at distance x from A.The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x) / x
(c) W(d-x) / d
(d) Wx / d
Correct Answer:
W(d-x) / d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
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Subject: Physics
(2479)
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