| ⇦ | 
| ⇨ |
A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium, in a horizontal position.The knives are at a distance d from each other.The centre of mass of the rod is at distance x from A.The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x) / x
(c) W(d-x) / d
(d) Wx / d
Correct Answer:
W(d-x) / d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- The distance of the moon form the earth is 3.8×10⁵ km. Supposing that the eye
- A roller coaster is designed such that riders experience “weightlessness” as they
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- The distance of the moon form the earth is 3.8×10⁵ km. Supposing that the eye
- A roller coaster is designed such that riders experience “weightlessness” as they
- A straight conductor of length 0.4 m is moved with a speed of 7 ms⁻¹perpendicular
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply