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A rod of weight W is supported by two parallel knife edge A and B and is in equilibrium, in a horizontal position.The knives are at a distance d from each other.The centre of mass of the rod is at distance x from A.The normal reaction on A is
Options
(a) Wd/x
(b) W(d-x) / x
(c) W(d-x) / d
(d) Wx / d
Correct Answer:
W(d-x) / d
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
- At what angle should the two forces 2P and √2 P act,so that the resultant force is P√10?
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- A susceptibility of a certain magnetic material is 400. What is the class
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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