| ⇦ | 
| ⇨ |
A resistance of 20 ohm is connected to a source of an alternating potential V=220 sin (100 πt). The time taken by the current to change from its peak value to r.m.s value is
Options
(a) 2.5 x 10⁻³ sec
(b) 0.25 sec
(c) 25 x 10⁻³ sec
(d) 2.5 sec
Correct Answer:
2.5 x 10⁻³ sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Length of second pendulum is
- Time taken by light to cross a glass slab of thickness 4 mm and refractive index 3 is
- A ray of light travelling in a transparent medium of refractive index µ, falls on surface
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Length of second pendulum is
- Time taken by light to cross a glass slab of thickness 4 mm and refractive index 3 is
- A ray of light travelling in a transparent medium of refractive index µ, falls on surface
- Two spherical conductors A and B of radii 1 mm and 2 mm are separated by a distance
- A body rolls down a stair case of 5 steps. Each step has height 0.1 m and width 0.1m
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply