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A ray of light passes from a medium A having refractive index 1.6 to the medium B having refractive index 1.5. The value of critical angle of medium A is……..
Options
(a) sin⁻¹ √16/15
(b) sin⁻¹(16/15)
(c) sin⁻¹(1/2)
(d) sin⁻¹(15/16)
Correct Answer:
sin⁻¹(15/16)
Explanation:
As the law of refraction, we have
sin i(c) / sin 90° = 1.5 / 1.6
Therefore sin i(c) = 15 / 16
where i(c) = critical angle of medium, A = sin⁻¹ (15 / 16)
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Topics: Ray Optics
(94)
Subject: Physics
(2479)
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