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A radioactive substance decays to 1/16th of its initial activity in 40 days. The half-life of the radioactive substance expressed in days is
Options
(a) 2.5
(b) 5
(c) 10
(d) 20
Correct Answer:
10
Explanation:
N/N₀ = (1/2)ⁿ
(1/16) = (1/2)ⁿ
n = 4
Half life = t / n = 40 / 4 = 10 day
Related Questions: - The ratio of specific charge of an α-particle to that of a proton is
- An objective moves ,starting from rest through a resistive medium
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- Which of the following statements is correct?
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of specific charge of an α-particle to that of a proton is
- An objective moves ,starting from rest through a resistive medium
- In forward biasing of the p-n junction
- A boy whirls a stone in a horizontal circle of radius 1.5 m and at height 2.0 m
- Which of the following statements is correct?
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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