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A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane motion, the proton will move in a circular path of radius
Options
(a) 2Em/qB
(b) √2Em/qB
(c) √Em/2qB
(d) √2Eq/qB
Correct Answer:
√2Em/qB
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
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