| ⇦ |
| ⇨ |
A proton of mass 1.6×10⁻²⁷ kg goes round in a circular orbit of radius 0.10 m under a centripetal force of 4×10⁻¹³ N. The frequency of revolution of the proton is about
Options
(a) 0.08×10⁸ cps
(b) 4×10⁸ cps
(c) 8×10⁸ cps
(d) 12×10⁸ cps
Correct Answer:
0.08×10⁸ cps
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A source is moving towards an observer with a speed of 20 m/s and having frequency
- The valence band and the conductance band of a solid overlap at low temperature
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal
- A body projected vertically from the earth reaches a height equal to earth’s radius
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A source is moving towards an observer with a speed of 20 m/s and having frequency
- The valence band and the conductance band of a solid overlap at low temperature
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- A bar magnet having a magnetic moment of 2 x 10⁴JT⁻¹ is free to rotate in a horizontal
- A body projected vertically from the earth reaches a height equal to earth’s radius
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply