| ⇦ | 
| ⇨ |
A proton is projected with a speed of 3×10⁶ m/s horizontally from east to west. An uniform magnetic field of strength 2×10⁻³ T exist in the vertically upward direction. What would be the acceleration of proton?
Options
(a) 11.6×10¹¹ m/ s²
(b) 17.4×10¹¹ m/ s
(c) 5.8×10¹¹ m/ s²
(d) 2.9×10¹¹ m/ s²
Correct Answer:
5.8×10¹¹ m/ s²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two radiations of photons energies 1 eV and 2.5 eV, successively
- The logic behind NOR gate is that it gives
- In R-L-C series circuit, the potential differences across each element is 20 V.
- When aluminium is added as an impurity to silicon, the resulting material is
- MA⁻¹T⁻² is the dimensional formula of
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- The logic behind NOR gate is that it gives
- In R-L-C series circuit, the potential differences across each element is 20 V.
- When aluminium is added as an impurity to silicon, the resulting material is
- MA⁻¹T⁻² is the dimensional formula of
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply