| ⇦ | 
| ⇨ |
A projectile is fired at an angle of 45° with the horizontal. Elevation angle of the projectile at its highest point as seen from the point of projection is
Options
(a) 60°
(b) tan⁻¹(1/2)
(c) tan⁻¹(√3/2)
(d) 45°
Correct Answer:
tan⁻¹(1/2)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours.
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- The potential difference that must be applied to stop the fastest photoelectrons
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- White light reflected from a soap film (Refractive Index =1.5) has a maxima
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The radioactivity of a certain material drops to 1/16 of the initial value in 2 hours.
- A particle of mass ‘m’ is kept at rest at a height 3R from the surface of earth
- The potential difference that must be applied to stop the fastest photoelectrons
- In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω,
- White light reflected from a soap film (Refractive Index =1.5) has a maxima
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply