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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- If r denotes the distance between sun and the earth, then the angular momentum of the earth
- Two liquid drops having diameters of 1 cm and 1.5 cm. The ratio of excess
- An α-particle and a proton are accelerated through same potential difference
- The work function for aluminium is 4.125 eV. The cutoff wavelength for photoelectric
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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