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A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ, where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x is given by
Options
(a) -2nb²x⁻⁴ⁿ⁻¹
(b) -2nb²x⁻²ⁿ⁺¹
(c) -2nb²e⁻⁴ⁿ⁺¹
(d) -2nb²x⁻²ⁿ⁻¹
Correct Answer:
-2nb²x⁻⁴ⁿ⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A step-down transformer has 50 turns on secondary and 1000 turns on primary winding.
- A beam of light contains two wavelengths 6500Å and 5200Å.
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- Time period of the rotation of the earth about its own axis is 24 hour
- Huygen’s principle of secondary wavelets may be used to
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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