| ⇦ | 
| ⇨ |
A particle of mass m is projected with velocity v making an angle of 45° with the horizontal. When the particle lands on the level ground the magnitude of the change in its momentum will be:
Options
(a) 2mv
(b) mv/√2
(c) mv√2
(d) zero
Correct Answer:
mv√2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- A spring has time period T. It is cut into n equal parts. The time period of each part
- Which of the following rods of same material undergoes maximum elongation
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin equiconvex lens of refractive index 3/2 and radius of curvature 30 cm
- Thin uniform rod of length L, cross-sectional area A and density ρ is rotated
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- A spring has time period T. It is cut into n equal parts. The time period of each part
- Which of the following rods of same material undergoes maximum elongation
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply