A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T)

⇦

⇨

A particle moving along X-axis has acceleration f,at time t given by f=fₒ(1- t/T), where fₒ and T are constants. The particle’s velocity (vₓ) is

Options

(a) fₒT
(b) (1/2)fₒT²
(c) fₒT²
(d) (1/2)fₒT

Correct Answer:

(1/2)fₒT

Explanation:

Acceleration, f = dv/dt = f₀[1-(t/T)]
dv = f₀[1-(t/T)]dt —–(i)
On integrating Equation (i) both sides, we get
.·. v = f₀t – (f₀/T)(t²/2)dt + C —–(ii)
After applying boundery conditions v = 0 at t = 0, we get
Therefore, C = 0
v = f₀t – (f₀/T)(t²/2)dt —–(iii)
As, f = f₀[1-(t/T)]
When, f = 0,t = T
Substituting, t = T in Equation (iii), then velocity
vₓ = f₀T – (f₀/T)(T²/2)
= f₀T – (1/2)f₀T = (1/2)fₒT

Related Questions:

1. A pan is suspended from a steel wire. Weights are slowly put on the pan
2. A spring of spring constant 5 x 10³ Nm⁻¹ is streched intially by 5 cm from
3. Two balls are dropped from same height at 1 second interval of time.
4. A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
5. The frequencies of X-rays,γ-rays and ultraviolet rays are respectively p,q and r

Topics: Motion in Straight Line (93)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends