| ⇦ |
| ⇨ |
A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - A device which converts electrical energy into mechanical energy is
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- If the angular momentum of any rotating body increase by 200 % , then the increase
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- Zenor breakdown will occur if
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A device which converts electrical energy into mechanical energy is
- Ratio of the radii of the nuclei with mass numbers 8 and 27 would be
- If the angular momentum of any rotating body increase by 200 % , then the increase
- If M (A; Z), Mₚ and Mₙ denote the masses of the nucleus AZ X, proton
- Zenor breakdown will occur if
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply