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A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - A certain number of spherical dropes of a liquid of radius r coalesce to form a single
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Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A certain number of spherical dropes of a liquid of radius r coalesce to form a single
- During an adiabatic process, the cube of the pressure is found to be inversely
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
- The volume of a nucleus is directly proportional to
- An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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