| ⇦ | 
| ⇨ |
A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is
Options
(a) 2π√x₂²-x₁²/V₁²-V₂²
(b) 2π√V₁²+V₂²/x₂²+x₁²
(c) 2π√V₁²-V₂²/x₁²-x₂²
(d) 2π√x₁²-x₂²/V₁²-V₂²
Correct Answer:
2π√x₂²-x₁²/V₁²-V₂²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
- The speed of electromagnetic waves in vaccum is equal to
- For an ideal gas of diatomic molecules
- Two discs of same material and thickness have radii 0.2 m and 0.6 m.
- When a ceiling fan is switched on, it makes 10 revolutions in the first 3s
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The maximum and minimum intensities of two sources is 4:1. The ratio of amplitude is
- The speed of electromagnetic waves in vaccum is equal to
- For an ideal gas of diatomic molecules
- Two discs of same material and thickness have radii 0.2 m and 0.6 m.
- When a ceiling fan is switched on, it makes 10 revolutions in the first 3s
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply