⇦ | ![]() | ⇨ |
A particle is executing SHM along a straight line. Its velocities at distances x₁ and x₂ from the mean position are V₁ and V₂ respectively. Its time period is
Options
(a) 2π√x₂²-x₁²/V₁²-V₂²
(b) 2π√V₁²+V₂²/x₂²+x₁²
(c) 2π√V₁²-V₂²/x₁²-x₂²
(d) 2π√x₁²-x₂²/V₁²-V₂²
Correct Answer:
2π√x₂²-x₁²/V₁²-V₂²
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped
- A conducting square frame of side ‘a’ and a long straight wire carrying current I
- A radioactive nucleus emits a beta particle. The parent and daughter nuclei are
- When two displacements represented by y₁=a sin(?t) are superimposed the motion is
- If the kinetic energy of the particle is increased to 16 times its previous value
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply