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A particle in simple harmonic motion is described by the displacement function x(t) = A cos(wt+θ). If the initial (t=0) position of the particle is 1 cm, its initial velocity is π cm/s, and its angular speed is π radian/sec, then its amplitude is
Options
(a) 1 cm
(b) √2 cm
(c) 2 cm
(d) 2.5 cm
Correct Answer:
√2 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude
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- In which of the follows decays, the element does not change?
- A balloon with mass m is descending down with an acceleration a
- Three unequal resistors in parallel are equivalent to a resistance 1 Ω.
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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