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A particle has initial velocity (2i⃗+3j⃗) and acceleration (0.3i⃗+0.2j⃗). The magnitude of velocity after 10 seconds will be:
Options
(a) 9 √2 units
(b) 5 √2 units
(c) 5 units
(d) 9 units
Correct Answer:
5 √2 units
Explanation:
v⃗ = u⃗ + a⃗t
v = (2i + 3j) + (0.3i + 0.2j) x 10 = 5i +5j
| v⃗ | = √ (5² + 5²)
| v⃗ | = 5 √2
Related Questions: - An electron is moving in a circular path under the influence of a transverse magnetic
- If the kinetic energy of the particle is increased to 16 times its previous value
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
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Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron is moving in a circular path under the influence of a transverse magnetic
- If the kinetic energy of the particle is increased to 16 times its previous value
- A bimetallic strip consists of metals X and Y. It is mounted rigidly at the base as shown
- An unpolarised beam of intensity I₀ falls on a polaroid. The intensity
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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