A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)

A Particle Free To Move Along Xaxis Has Potential Energy Physics Question

A particle free to move along X-axis has potential energy given as U(X) =k(1-e-ˣ²),where k is a positive constant of appropriate dimension.Then, for -a

Options

(a) at points away from the origin, the particle is in unstable equilibrium
(b) for any finite non-zero value of x,there is a force directed away from the origin
(c) if its total mechanical energy isk/2, it has its minimum kinetic energy at the origin
(d) if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Correct Answer:

if its total mechanical energy isk/2, it has its maximum kinetic energy at the origin

Explanation:

No explanation available. Be the first to write the explanation for this question by commenting below.

Related Questions:

  1. An artificial satellite is revolving round the earth in a circular orbit. Its velocity
  2. Ionization potential of hydrogen atom is 13.6 eV. Hydrogen atoms in the ground state
  3. If a gymnast, sitting on a rotating stool with his arms outstretched, suddenly
  4. A ray of light travelling in a transparent medium of refractive index µ, falls on surface
  5. A body is moving with velocity 30 m/s towards east. After 10 seconds its velocity

Topics: Work Energy and Power (94)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*