⇦ | ![]() | ⇨ |
A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times taken by it in going from its mean position to 2 cm and from 2 cm to extreme position is
Options
(a) 1
(b) 1/3
(c) 1/4
(d) 1/2
Correct Answer:
1/2
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- An electron is
- The relationship between decay constant λ and half-life T of a radioactive substance is
- A wire of resistance 4 ohm is stretched to twice its original length.
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- A wire mesh consisting of very small squares is viewed at a distance
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply