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A particle covers half of its total distance with speed v1 and the rest half distance with speed v2. Its average speed during the complete journey is
Options
(a) (v1v2)/(v1+v2)
(b) (2v1v2)/(v1+v2)
(c) (2v1²v2²)/(v1²+v2²)
(d) (v1+v2)/2
Correct Answer:
(2v1v2)/(v1+v2)
Explanation:
Let the tot. distance covered by the particles be 2s. Then
vₐᵥ = 2 s / (s/ v₁ + s/ v₂) = 2 v₁v₂ / v₁ + v₂
Related Questions: - A nucleus disintegrates into two nuclear parts which have their velocities in the ratio
- The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.
- X-ray beam can be deflected by
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A nucleus disintegrates into two nuclear parts which have their velocities in the ratio
- The root mean square speed of oxygen molecule (O₂) at a certain temperature is v.
- X-ray beam can be deflected by
- A 1 µA beam of protons with a cross-sectional area of 0.5 sq.mm is moving with a velocity
- The core of a transformer is laminated because
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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