| ⇦ | 
| ⇨ |
A parallel beam of light of wavelength λ is incident normally on a narrow slit. A diffraction pattern is formed on a screen placed perpendicular to the direction of the incident beam. At the second minimum of the diffraction pattern, the phase difference between the rays coming from the two edges of slit is
Options
(a) πλ
(b) 2π
(c) 3π
(d) 4π
Correct Answer:
4π
Explanation:
Condition for the diffraction minima are
Path diff. ∆x = nλ and Phase diff. ?ﾝﾜﾙ = 2nπ
Path diff. = nλ = 2λ
Phase diff. = 2nπ = 4π (n=2)
Related Questions: - A student measures the terminal potential difference (V) of a cell
- A polished metal plate has a rough and black-spot. It is heated to 1400 K
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A student measures the terminal potential difference (V) of a cell
- A polished metal plate has a rough and black-spot. It is heated to 1400 K
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
- The time of reverberation of a room A is one second. What will be the time (in seconds)
- Copper of fixed volume V is drawn into wire of length l. When this wire is subjected
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply