| ⇦ | 
| ⇨ |
A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - A horizontal straight conductor kept in north-south direction falls under gravity. Then
- What is the energy released by fission of 1 g of U²³⁵?
- Dimensional formula of magnetic field in terms of mass M, length L
- In N-type semi-conductor current is due to
- The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A horizontal straight conductor kept in north-south direction falls under gravity. Then
- What is the energy released by fission of 1 g of U²³⁵?
- Dimensional formula of magnetic field in terms of mass M, length L
- In N-type semi-conductor current is due to
- The focal lengths of a converging lens are fᵥ and fᵣ for violet and red lights
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply