| ⇦ | 
| ⇨ |
A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter nucleus is
Options
(a) A-4/4v
(b) 4v/A-4
(c) v
(d) v/4
Correct Answer:
4v/A-4
Explanation:
According to the question, zXᴬ → z-₂ Yᴬ⁻⁴ + ₂He⁴
Let the recoil speed of daughter nucleus is ʋ’. By the law of conservation of momentum, we have Initial momentum = Final momentum
0 = (A – 4)ʋ’ + 4ʋ
(A – 4) ʋ’ = -4ʋ ⇒ ʋ’ = 4ʋ / (A – 4)
Related Questions: - A radioactive element forms its own isotope after 3 consecutive disintegrations.
- When we close one slit in the young’s double slit experiment, then
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- When a spring is extended by 2 cm energy stored is 100 J. When extended further by 2 cm
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A radioactive element forms its own isotope after 3 consecutive disintegrations.
- When we close one slit in the young’s double slit experiment, then
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
- The e.m.f. of a battery is 2 V and its internal resistance is 0.5 Ω. The maximum
- When a spring is extended by 2 cm energy stored is 100 J. When extended further by 2 cm
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply