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A nucleus ᵐₙ X emits one α- particle and two β- particles. The resulting nucleus is
Options
(a) ᵐ⁻⁶ₙ₋₄ Z
(b) ᵐ⁻⁶ₙ Z
(c) ᵐ⁻⁴ₙ X
(d) ᵐ⁻⁴ₙ₋₂ Y
Correct Answer:
ᵐ⁻⁴ₙ X
Explanation:
When ᵐₙ X emits one α- particle then its atomic mass decreases by 4 units and atomic number4 by 2. Therefore, the new nucleus becomes ᵐ⁻⁴ₙ₋₂ Y. But as it emits two β⁻ particles, its atomic number incre4ases by 2. Thus the resulting nucleus is ᵐ⁻⁴ₙ X.
Related Questions: - A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- If α (current gain) of transistor is 0.98, then what is the value of β
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Carnot engine takes heat from a reservoir at 627⁰C and rejects heat
- If ₉₂U²³⁸ undergoes successively 8 ∝-decays and 6 β-decays, the resulting nucleus is
- A conductor of length 5 cm is moved parallel to itself with a speed of 2 m/s,
- If α (current gain) of transistor is 0.98, then what is the value of β
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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