| ⇦ |
| ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A wire of one metre length carries a constant current. The wire is bent to form
- When the angle of incidence is 60° on the surface of a glass slab, it is found
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- At a given temperature the root mean square velocities of oxygen and hydrogen
- The electron of a hydrogen atom revolves round the proton in a circular
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire of one metre length carries a constant current. The wire is bent to form
- When the angle of incidence is 60° on the surface of a glass slab, it is found
- The transition from the state 3 n = 3 to n = 1 in a hydrogen like atom results
- At a given temperature the root mean square velocities of oxygen and hydrogen
- The electron of a hydrogen atom revolves round the proton in a circular
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply