| ⇦ | 
| ⇨ |
A metal conductor of length 1m rotates vertically about one of its ends at angular velocity 5 radian per second. If the horizontal component of earth’s magnetic field is 0.2×10⁻⁴ T, then the e.m.f. developed between the two ends of the conductor is
Options
(a) 5 μV
(b) 50 mV
(c) 5 mV
(d) 50 μV
Correct Answer:
50 mV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An engine has an efficiency of 1/6. When the temperature of sink is reduced
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- A charged particle experiences magnetic force in the presence of magnetic field.
- An automobile moves on a road with a speed of 54 km h⁻¹. The radius of its wheels
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An engine has an efficiency of 1/6. When the temperature of sink is reduced
- A particle has initial velocity (3i + 4j) and acceleration (0.1 i+0.3j). It’s speed after 10s
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
- A charged particle experiences magnetic force in the presence of magnetic field.
- An automobile moves on a road with a speed of 54 km h⁻¹. The radius of its wheels
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply