| ⇦ | 
| ⇨ |
A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - The ratio of minimum wavelengths of Lyman and Balmer series will be
- Potential at a point x-distance from the centre inside the conducting sphere
- In common base circuit of a transistor, current amplification factor is 0.95.
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of minimum wavelengths of Lyman and Balmer series will be
- Potential at a point x-distance from the centre inside the conducting sphere
- In common base circuit of a transistor, current amplification factor is 0.95.
- When a ball is thrown up vertically with velocity vₒ,it reaches a maximum height
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply