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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- The electric potential V at any point (x,y,z) all in meters in space is given by
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- If potential(in volts) in a region is expressed as V(x,y,z) = 6xy – y + 2yz,
- The electric potential V at any point (x,y,z) all in meters in space is given by
- A thin rod of length L and mass M is bent at its midpoint into two halves
- Ring, hollow ring and solid sphere are rolled down from inclined plane
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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