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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- If a small sphere is let fall vertically in a large quantity of still liquid of density
- An engine is moving towards a wall with a velocity 50 ms⁻¹ emits a note of 1.2 kHz.
- The mass of a ⁷₃ Li nucleus is 0.042 u less than the sum of the masses of all its nucleons
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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