| ⇦ | 
| ⇨ |
A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - Two balls of mass m₁ and m₂ are separated from each other by powder charge
- A particle of mass m is projected with velocity v making an angle of 45° with
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two balls of mass m₁ and m₂ are separated from each other by powder charge
- A particle of mass m is projected with velocity v making an angle of 45° with
- A boy is trying to start a fire by focusing sunlight on a piece of paper using
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply