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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
Related Questions: - A machine gun fires 10 bullets/s,each of mass 10 g,the speed of each bullet
- A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.
- Two pendulums A and B are oscillating simultaneously with time period
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A machine gun fires 10 bullets/s,each of mass 10 g,the speed of each bullet
- A meter stick of mass 400 g is pivoted at one end and displaced through an angle 60°.
- Two pendulums A and B are oscillating simultaneously with time period
- The resistance of an ammeter is 13Ω and its scale is graduated for a current
- Three capacitors of capacitances 3 μF, 10 μF and 15 μF are connected in series
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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