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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is
Options
(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06
Correct Answer:
0.06
Explanation:
From equation of motion, v = u – at
⇒ o = u – μgt
⇒ μ = u/gt
= 6/(10×10)
= 0.06
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following combinations should be selected for better tuning of an L-C-R
- In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
- A spherical drop of capacitance 1μF is broken into eight drops of equal radius.
- When a light beam of frequency v is incident on a metal surface,
- The upper half of an inclined plane of inclination θ is perfectly smooth while lower
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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