A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped

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A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 sec. Then the coefficient of friction is

Options

(a) 0.01
(b) 0.02
(c) 0.03
(d) 0.06

Correct Answer:

0.06

Explanation:

From equation of motion, v = u – at

⇒ o = u – μgt

⇒ μ = u/gt

= 6/(10×10)

= 0.06

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Topics: Laws of Motion (103)
Subject: Physics (2479)

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