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A light whose frequency is equal to 6.0 x 10¹⁴ Hz is incident on a metal whose work function is 2 eV. (h= 6.63 x 10⁻³⁴ Js, 1 ev = 1.6 x 10⁻¹⁹ J). The maximum energy of the electron emitted will be
Options
(a) 2.49 eV
(b) 4.49 eV
(c) 0.49 eV
(d) 5.49 eV
Correct Answer:
0.49 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A metal conductor of length 1m rotates vertically about one of its ends at angular
- A proton and helium nucleus are shot into a magnetic field at right angles to the field
- A bullet of mass 0.05 kg moving with a speed of 80 m/s enters a wooden
- If the velocity of an electron increases, then its de Broglie wavelength will
- Charge q is uniformly spread on a thin ring of radius R. The ring rotates
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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