| ⇦ | 
| ⇨ |
A L-C-R circuit with L=1.00 mH, C=10μF and R=50Ω, is driven with 5 V AC voltage. At resonance, the current through the circuit is
Options
(a) 0.2 A
(b) 0.25 A
(c) 0.15 A
(d) 0.1 A
Correct Answer:
0.1 A
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- What is the difference between soft and hard X-ray?
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- The angular momentum of an electron is J. The magnitude of the magnetic moment
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- What is the difference between soft and hard X-ray?
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply