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A hemispherical bowl of radius R is rotating about its axis of symmetry which is kept vertical.A small ball kept in the bowl rotates with the bowl without sliiping on its surface.If the surface of the bowl is smooth and the angle made by the radius through the ball with the vertical is α.Find the angular speed at which the bowl is rotating.
Options
(a) √(g / R sinα)
(b) √(g / R cosα)
(c) g√(1 / R cosα)
(d) g√(1 / R sinα)
Correct Answer:
√(g / R cosα)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- The ratio of specific heats Cp/Cv=γ in terms of degrees of freedom (n) is given by
- Calcium plate has a maximum possible radiation wavelength 400 nm to eject electrons.
- The binding energy per nucleon of ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06MeV
- The ionisation potential of hydrogen-atom is -13.6 eV. An electron in the groundstate
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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