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A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?¬ネレ(l/g)
(b) t = 2?¬ネレ(lsinθ/g)
(c) t = 2?¬ネレ(lcosθ/g)
(d) t = 2?¬ネレ(l/g cosθ)
Correct Answer:
t = 2?¬ネレ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the difference between soft and hard X-ray?
- In a potentiometer experiment, the balancing with a cell is at length 240 cm.
- The radius of orbit of a planet is two times that of the earth. The time period
- Photoelectric emision occurs only when the incident light has more than a certain minimum
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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