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A heavy small sized sphere is suspended by a string of length l.The sphere rotates uniformly in a horizontal circle with the string making an angle θ with the vertical.Then, the time-period of this conical pendulum is
Options
(a) t = 2?￢ﾈﾚ(l/g)
(b) t = 2?￢ﾈﾚ(lsinθ/g)
(c) t = 2?￢ﾈﾚ(lcosθ/g)
(d) t = 2?￢ﾈﾚ(l/g cosθ)
Correct Answer:
t = 2?￢ﾈﾚ(lcosθ/g)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A small object of uniform density rolls up a curved surface with an initial velocity
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- Moment of inertia, along the diameter of a ring is
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A small object of uniform density rolls up a curved surface with an initial velocity
- The number of photons of wavelength of 540 nm emitted per second by an electric bulb
- Moment of inertia, along the diameter of a ring is
- Unit of reduction factor is
- The focal length of the objective of a terrestrial telescope is 80 cm
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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