⇦ | ⇨ |
A gas has a vapour density 11.2.The volume occupied by 1 g of gas at NTP is
Options
(a) 1 litre
(b) 11.2 litre
(c) 22.4 litre
(d) unpredictable
Correct Answer:
1 litre
Explanation:
Given, vapour density = 11.2. Therefore Molecular weight = 2 x 11.2 = 22.4. Now, ·.· at NTP 22.4 g of gas occupies = 22.4 litres. .·. At NTP 1 g gas occupies = 22.4 / 22.4 = 1 litre.
Related Questions: - Pauling’s electro negativity values for elements are useful in predicting
- Nitrogen dioxide and sulphur dioxide have some properties in common.
- The hybridised state of N in R₂NH is
- Hydro-metallurgical process of extraction of metals is based on
- An aqueous solution of glucose is 10% in strength. The volume in which 1g mole
Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Pauling’s electro negativity values for elements are useful in predicting
- Nitrogen dioxide and sulphur dioxide have some properties in common.
- The hybridised state of N in R₂NH is
- Hydro-metallurgical process of extraction of metals is based on
- An aqueous solution of glucose is 10% in strength. The volume in which 1g mole
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply