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A gas has a vapour density 11.2.The volume occupied by 1 g of gas at NTP is
Options
(a) 1 litre
(b) 11.2 litre
(c) 22.4 litre
(d) unpredictable
Correct Answer:
1 litre
Explanation:
Given, vapour density = 11.2. Therefore Molecular weight = 2 x 11.2 = 22.4. Now, ·.· at NTP 22.4 g of gas occupies = 22.4 litres. .·. At NTP 1 g gas occupies = 22.4 / 22.4 = 1 litre.
Related Questions: - The number of optical isomers formed by hydrogenation of the compound (CH₃)₂C=CHCH₃
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Topics: States of Matter Gases and Liquids
(80)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The number of optical isomers formed by hydrogenation of the compound (CH₃)₂C=CHCH₃
- The solubility of CuBr is 2 ˣ 10⁻⁴ mol/L at 25⁰C. The Ksp value for CuBr is
- Which has the maximum number of molecules among the following
- The amount of zinc required to produce 224mL of H₂ at STP on treatment with dilute H₂SO₄
- In the equation of state of an ideal gas PV = nRT, the value of the universal gas
Topics: States of Matter Gases and Liquids (80)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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