⇦ | ⇨ |
A force F=ai+3j+6k is acting at a point r=2i-6j-12k. The value of α for which angular momentum about origin is conserved is
Options
(a) 2
(b) zero
(c) 1
(d) -1
Correct Answer:
-1
Explanation:
From Newton’s second law for rotational motion,
τ = dL / dt, if L = constant then τ = 0
So, τ = r × F = 0
(2î – 6ĵ – 12k̂) × (αî + 3ĵ + 6k̂) = 0
Solving we get α = -1.
Related Questions: - Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- In an NPN transistor the collector current is 24 mA. If 80% of the electrons
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- Charge Q is divided into two parts which are then kept some distance apart. The force
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
Topics: Motion of system of Particles and Rigid Body
(73)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- In an NPN transistor the collector current is 24 mA. If 80% of the electrons
- The displacement of a particle along the x-axis is given by x = a sin² ?t
- Charge Q is divided into two parts which are then kept some distance apart. The force
- An object is 8 cm high. It is desired to form a real image 4 cm high at 60 cm from
Topics: Motion of system of Particles and Rigid Body (73)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply