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A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bomb of mass 16 kg at rest explodes into two pieces of masses of 4 kg and 12 kg.
- The string of a pendulum is horizontal.The mass of bob attached to it is m
- When the wave of hydrogen atom comes from infinity into the first orbit,
- Two satellites of earth, S₁ and S₂ are moving in the same orbit. The mass of S₁
- A body of length 1 m having cross-sectional area 0.75 m² has heat flow through it
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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