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A force acts on a 3.0 g particle in such a way that the position of the particle as a function of time is given by x = 3t – 4t² + t³ , where x is in metre and t is in second. The work done during the first 4 s is
Options
(a) 570 mj
(b) 450 mj
(c) 490 mj
(d) 530 mj
Correct Answer:
530 mj
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- The equivalent resistance of two resistors connected in series is 6 Ω
- The acceleration due to gravity near the surface of a planet of radius R and density d
- Two metal rods 1 and 2 of same lengths have same temperature difference
- Vectors A⃗, B⃗ and C⃗ are such that A⃗ . B⃗ = 0 and A⃗ . C⃗ = 0 Then the vector parallel
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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