| ⇦ |
| ⇨ |
A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic field of strength 0.1 tesla. Net induced emf is
Options
(a) 2 π x 10⁻² V
(b) 4 π x 10⁻² V
(c) π x 10⁻² V
(d) 3 π x 10⁻² V
Correct Answer:
π x 10⁻² V
Explanation:
Induced emf = Baʋ
= 0.1 × π (0.1)² × 10
= 0.1 × 0.1π × 10
= π × 10⁻³ × 10
= π × 10⁻² V
Related Questions: - The mass number of nucleus is always
- A neutron moving with velocity v collides with a stationary particle
- The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mass number of nucleus is always
- A neutron moving with velocity v collides with a stationary particle
- The surface tension of soap solution is 0.03 N/m. The work done in blowing to form a soap
- A black body at 227⁰C radiates heat at the rate of 7cals/cm²s. At a temperature
- Two metallic spheres of radii 1 cm and 3 cm are given charges of -1 x 10⁻² C
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply