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A current of 2A flows through a 2Ω resistor when connected across a battery. The same battery supplies a current of 0.5A when connected across a 9Ω resistor. The internal resistance of the battery is
Options
(a) 0.5Ω
(b) 1/3Ω
(c) 1/4Ω
(d) 1Ω
Correct Answer:
1/3Ω
Explanation:
Let the internal resistance of the battery be r. Then the current flowing through the circuit is given by
i = E / R + r
In first case, 2 = E / 2 + r …(i)
In second case, 0.5 = E / 9 + r … (ii)
From (i) & (ii), 4 + 2r = 4.5 + 0.5r
1.5r = 0.5
r = 1/3Ω
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Topics: Current Electricity
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two masses of 9 g and 6 g are connected with a string which is passing over a frictionless
- A copper disc of radius 0.1 m is rotated about its centre, with 10 revolutions
- Two identical charges repel each other with a force equal to 10 mgwt they are 0.6 m
- In stretching a spring by 2 cm, energy stored is given by U. Had is been stretched
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
Topics: Current Electricity (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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